# Euler Problem 006

## Mar 23, 2018 09:03 · 207 words · 1 minute read

### The problem

The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + … + 10^2 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + … + 10)^2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

#### Solution

The code is not that interesting. You simply walk from 1 to the number keeping track of the differences and return them in the end. Not a bad way to warm up for the day, but definitely isn’t going to keep thinking forever.

```
var findDifferenceOfSquares = function(number){
var differences = [];
var sum = 0;
var sumOfSquares = 0;
for(var i = 1; i < number + 1; i++) {
sum += i;
sumOfSquares += i * i;
differences.push(sum*sum - sumOfSquares);
}
return differences;
}
```

If you’d like to see the full code please see my daily toy problem exercises that I’ve been working on. It includes tests and a README.